Oh good grief! poster wrote or copied:299,792,458 meters per second

I'm convinced it has to be this speed to allow a quantum/classical boundary. A Femtosecond holds the key of 0.3 micrometers. An object with this width is going to be auto-observed ..have a physical state. The speed of light is the speed it is in order for quantum events to occur. If it was any faster a Femtosecond could cover 0.2 micrometers and prevent quantum weirdness from being a thing.

The speed of light is directly tied to the spaceTime and it seems to be a frame rate.

I suspect the default speed of light is actually 200,000,000 m/s and a multiplier of1.49896229is added to the frame rate to equal 299,792,458 m/s

Again, the multiplier is to ensure the quantum/classical boundary size.

If we take the speed of light and multiply it by 5 we get: 299,792,458 m/s x 5 =1.49896229×10^15 Micrometers per second (1,498,962,290,000,000)

I think it is telling us 1,498,962,290 m/s is the speed of light when spacetime isn't involved.

The speed of light gets divided by 5. Is it saying time gets split between 5 different dimensions?

299,792,458 m/s x 5 = 1,498,962,290 m/s or 1,498,962,290,000,000 Micrometers per second

1,498,962,290,000,000 / 5 = 2.9979246e+14 || 299,792,460,000,000

I think this is saying the auto-observe key is actually0.29979246 Micrometers

speed of light 299,792,458 / auto-observe 0.29979246 micrometers to meters 0.00000029979246 = 999,999,990,000,000

Light has a max of auto-observing 999,999,990,000,000 clumps of matter each second.

1000000000000000 - 999999990000000 = 10,000,000

I think that is somewhere around 1.00000001% of a difference.

"The official definition of a meter today is: 1⁄299792458 of the distance traveled bylightin a vacuum, in 1 second. ... A consequence of using this definition is that any attempt tomeasurethespeed of lightis cyclical; you must use a “meter” tomeasureit at some point, which relies on thespeed of light"

A Meter is based on 10's, it scales.

Time is Spacetime. I bring up the parallel universes because the math implies it. It can't be a coincidence that the speed of light x 5 equals that many micrometers.

You can rest assured a femtosecond of light is a unit of spacetime. The quantum/classical boundary demands it.

The split in 5 might be telling use there are 4 parallel universes.

https://www.nature.com/news/2010/100317/full/news.2010.130.html

This link says: 0.3 becomes 30 ..errr, maybe just for objects allowed to interact with 0.3 objects and not give them a physical state.

This explains why quantum weirdness events are allowed to occur in plants and animals.

Space and Time are directly tied. Or should I say Distance and Time? The frame rate of spacetime has been increased for light to be the speed it is.

If I'm right, the quantum/classical boundary should be different throughout the fabric of spacetime ..like time dilation.

Time dilation and the boundary must be insane in cosmic voids. This has to by why they are expanding.

Spacetime converts quantum waves that have a width of 0.3 or larger and automatically gives them a physical state. The wave is now also a particle, it is in a duality ..the quantum field and spacetime are influencing it. It isn't going to perform quantum weirdness events but will wobble like a wave. Observation can be performed on purpose with smaller objects ..what I care about are the auto-observed sizes.

Matter waves not decaying is pretty strong evidence that spacetime isn't involved with unobserved quantum waves.

Side thought: I don't think the quantum field has a causality limit for unobserved quantum waves.

The reason Einstein failed at a unifying theory is because he refused to believe anything could be without spacetime.

I think spacetime is available everywhere ..but is not enacted everywhere. I think Mass enacts it (the boundary).

If you toss a rock into a cosmic void, spacetime will form around its mass like a bubble. It will experience the maximum time dilation and quantum/classical boundary spacetime can handle. Because of the spacetime bubble size. If the rock is around the size of the new boundary (for its new bubble) it would disappear into quantum waves and so would the spacetime bubble (assuming the rock didn't have a physical state at the time).

Is this why we are seeing stars older than time? Are the stars in question living in cosmic voids?

Anything that ages, has a physical state.

lorentz doesn't apply to quantum waves without a physical state ..there is nothing to tradeoff

"The official definition of a meter today is: 1⁄299792458 of the distance traveled by

**light**in a vacuum, in 1 second. ... A consequence of using this definition is that any attempt to

**measure**the

**speed of light**is cyclical; you must use a “meter” to

**measure**it at some point, which relies on the

**speed of light"**

No, the length depends on the time. There is nothing circular. All the observer need do is create a 'stationary' frame of reference by erecting three mutually perpendicular axes, and measuring three equal lengths. Then rotating the axes and repeating the experiment. The result is that c is equal and constant in all three axes.

The sophomore will then inquire about time dilation due to proper motion, which is proportional to the value of gamma = 1/1-(v^2/c^2)^1/2 But this value also turns up in the formula for the Fitzgerald Contraction of lengths along the direction of motion.

objoke:

There once was a fellow named Fisk.

Whose fencing was exceedingly brisk.

So swift was his action,

the Fitzgerald Contraction,

reduced his rapier to a disk.

And while is is tempting to create a framework of physics in which we are possessed of six axes of time, I would pull out Occam's Razor to slice away that particular Rube Goldberg machinery.

Last edited: